4. A student throws a bag of chips to her friend. Unfortunately, herfriend does not catch the chips, and the bag hits the ground. Thedistance from the ground (height) for the bag of chips is modeledby the function h(t) 5 216(t 2 1)2 1 20, where h is the height(distance from the ground in feet) of the chips, and t is the numberof seconds the chips are in the air.A. Graph h(t) 5 216(t 2 1)2 1 20.B. From what height are the chips being thrown? Explain howyou know.C. What is the maximum height the bag ofchips reaches while airborne? Explain howyou know.D. About how many seconds a$er the bagwas thrown did it hit the ground?E. What is the average rate of change ofheight for the interval from 0 to 12 second?What does that number represent in termsof the context?F. Based on your answer to Part E, what is the average rate of change for the interval from1.5 to 2 sec.?© Tribalium/Shutterstock.com

(a)The function 𝑓(𝑡)=−5𝑡2+20𝑡+60f\left(t\right)=-5t^2+20t+60f(t)=−5t 2 +20t+60 models the approximate height of an object 𝑡tt seconds after it is launched. How many seconds does it take the object to hit the ground? (Enter only the number)

08.01 MC)A food packet is dropped from a helicopter and is modeled by the function f(x) = −15x2 + 6000. The graph below shows the height f(x), in feet, of the food packet at different times x, in seconds:Use the graph to determine the domain of f(x) for all viable x values based on the context.Group of answer choicesx ≤ 60000 ≤ x ≤ 20−20 ≤ x ≤ 20All real numbers

1. Jason jumped off a cliff into the ocean in Acapulco while vacationing with some friends. His height as a function of time could be modeled by the function h(t) = -16t² + 16t + 480, where t is the time in seconds and h is the height in feet.a. How long did it take for Jason to reach his maximum height?b. What was the highest point that Jason reached?c. Jason hit the water after how many seconds?

h=−4.9t 2 +25tThe equation above expresses the approximate height ℎ, in meters, of a ball 𝑡𝑡 seconds after it is launched vertically upward from the ground with an initial velocity of 25 meters per second. After approximately how many seconds will the ball hit the ground?A3.5B4.0C4.5D5.0

ProblemWhen a sprinkler is installed in the ground, the spray of water goes up and falls in the pattern of a parabola. The height, in inches, of a spray of water is given by the equation h(x)=160x−16x2ℎ(𝑥)=160𝑥−16𝑥2 where x𝑥 is the number of feet away from the sprinkler head the spray is. What is the height of the spray 22 feet away from the sprinkler head? Solutionh(2)=ℎ(2)= After 22 seconds, the height of the spray is inches.How many feet along the ground away from the sprinkler head will the spray reach a maximum height? feetWhat is the maximum height of the water spray? inchesHow many feet away from the sprinkler head will the water hit the ground again? feet