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Select the correct answerWhat will be the output of the following Java program? class CT {  public static void main(String args[]) {     try {      int X, Y;      Y = 0;      X = 5 / Y;      System.out.print("A");    }    catch(ArithmeticException e) {  System.out.print("B");    }    finally {     System.out.print("C");    }  } }OptionsAACBCB

Question

Select the correct answerWhat will be the output of the following Java program? class CT {  public static void main(String args[]) {     try {      int X, Y;      Y = 0;      X = 5 / Y;      System.out.print("A");    }    catch(ArithmeticException e) {  System.out.print("B");    }    finally {     System.out.print("C");    }  } }OptionsAACBCB

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Solution

The correct answer is B. The program will output "BC".

Here's the step by step explanation:

  1. The program starts with defining two integer variables X and Y. Y is set to 0.

  2. Then, the program tries to divide 5 by Y (which is 0). In Java, division by zero results in an ArithmeticException.

  3. The catch block catches this exception and the program prints "B".

  4. The finally block is always executed whether an exception is thrown or not. So, it prints "C".

  5. Therefore, the output of the program is "BC".

This problem has been solved

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