A heater supplies 10.2 kJ of thermal energy is to heat 80 grams of ice at 0C. The specific latent heat of fusion of ice is 340 J/g. How much ice remains after heating?
Question
A heater supplies 10.2 kJ of thermal energy is to heat 80 grams of ice at 0C. The specific latent heat of fusion of ice is 340 J/g. How much ice remains after heating?
Solution
Sure, let's solve this step by step:
Step 1: Convert the thermal energy supplied by the heater from kJ to J. 1 kJ = 1000 J So, 10.2 kJ = 10.2 * 1000 = 10200 J
Step 2: Calculate the amount of ice that can be melted by this amount of energy. The amount of ice that can be melted (in grams) = thermal energy supplied / specific latent heat of fusion of ice = 10200 J / 340 J/g = 30 g
Step 3: Subtract the amount of ice that was melted from the original amount to find out how much ice remains. Ice remaining = original amount - amount melted = 80 g - 30 g = 50 g
So, 50 grams of ice remains after heating.
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