Select the correct answerPredict the output of the given Java Program. class Tiger { private final void flipper() { System.out.println("Tiger"); } } class Cub extends Tiger { public final void flipper() { System.out.println("Cub"); } public static void main(String[] args) { new Cub().flipper(); }}OptionsCubTigerCompilation FailsNone of the mentioned
Question
Select the correct answerPredict the output of the given Java Program. class Tiger { private final void flipper() { System.out.println("Tiger"); } } class Cub extends Tiger { public final void flipper() { System.out.println("Cub"); } public static void main(String[] args) { new Cub().flipper(); }}OptionsCubTigerCompilation FailsNone of the mentioned
Solution
The correct answer is "Cub".
Here's the step by step explanation:
-
The
flipper()method in theTigerclass is declared asprivate, which means it can only be accessed within theTigerclass. It is also declared asfinal, which means it cannot be overridden. -
The
Cubclass extends theTigerclass. It also has aflipper()method, but this method is not an override of theflipper()method in theTigerclass because theflipper()method in theTigerclass isprivateand cannot be accessed from theCubclass. -
In the
mainmethod, a newCubobject is created and theflipper()method is called on this object. Since theCubclass has its ownflipper()method, this is the method that gets called, and "Cub" is printed to the console.
So, the output of the program is "Cub".
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