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Select the correct answerPredict the output of the given Java Program. class Tiger {    private final void flipper() {        System.out.println("Tiger");    } }   class Cub extends Tiger {    public final void flipper() {        System.out.println("Cub");    }    public static void main(String[] args) {         new Cub().flipper();    }}OptionsCubTigerCompilation FailsNone of the mentioned

Question

Select the correct answerPredict the output of the given Java Program. class Tiger {    private final void flipper() {        System.out.println("Tiger");    } }   class Cub extends Tiger {    public final void flipper() {        System.out.println("Cub");    }    public static void main(String[] args) {         new Cub().flipper();    }}OptionsCubTigerCompilation FailsNone of the mentioned

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Solution

The correct answer is "Cub".

Here's the step by step explanation:

  1. The flipper() method in the Tiger class is declared as private, which means it can only be accessed within the Tiger class. It is also declared as final, which means it cannot be overridden.

  2. The Cub class extends the Tiger class. It also has a flipper() method, but this method is not an override of the flipper() method in the Tiger class because the flipper() method in the Tiger class is private and cannot be accessed from the Cub class.

  3. In the main method, a new Cub object is created and the flipper() method is called on this object. Since the Cub class has its own flipper() method, this is the method that gets called, and "Cub" is printed to the console.

So, the output of the program is "Cub".

This problem has been solved

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