The electric force (F) acting on a charged particle in an electric field is given by the formula:

F = q * E

where:
q is the charge of the particle,
E is the intensity of the electric field.

Given:
q = -1.6 * 10^-19 C (the charge of an electron),
E = 10^4 N/C.

Substituting these values into the formula, we get:

F = -1.6 * 10^-19 C * 10^4 N/C
F = -1.6 * 10^-15 N

The negative sign indicates that the force is directed opposite to the direction of the electric field, which is expected since electrons are negatively charged and electric fields point in the direction that a positive charge would move. However, in terms of magnitude, the force is 1.6 * 10^-15 N.

So, the electric force acting on the electron is 1.6 * 10^-15 N. Therefore, the correct answer is d. 1.6 * 10^-15 N.

Question

The electric force (F) acting on a charged particle in an electric field is given by the formula:

F = q * E

where:
q is the charge of the particle,
E is the intensity of the electric field.

Given:
q = -1.6 * 10^-19 C (the charge of an electron),
E = 10^4 N/C.

Substituting these values into the formula, we get:

F = -1.6 * 10^-19 C * 10^4 N/C
F = -1.6 * 10^-15 N

The negative sign indicates that the force is directed opposite to the direction of the electric field, which is expected since electrons are negatively charged and electric fields point in the direction that a positive charge would move. However, in terms of magnitude, the force is 1.6 * 10^-15 N.

So, the electric force acting on the electron is 1.6 * 10^-15 N. Therefore, the correct answer is d. 1.6 * 10^-15 N.

Knowee AI · Accepted Answer

The electric force (F) acting on a charged particle in an electric field is given by the formula:

F = q * E

where:
q is the charge of the particle,
E is the intensity of the electric field.

Given:
q = -1.6 * 10^-19 C (the charge of an electron),
E = 10^4 N/C.

Substituting these values into the formula, we get:

F = -1.6 * 10^-19 C * 10^4 N/C
F = -1.6 * 10^-15 N

The negative sign indicates that the force is directed opposite to the direction of the electric field, which is expected since electrons are negatively charged and electric fields point in the direction that a positive charge would move. However, in terms of magnitude, the force is 1.6 * 10^-15 N.

So, the electric force acting on the electron is 1.6 * 10^-15 N. Therefore, the correct answer is d. 1.6 * 10^-15 N.

An electron is placed in an electric field of intensity 104 Newton per Coulomb. The electric force working on the electron is:a.0.625×1013Nb.0.625×10-15Nc.1.6x1015Nd.1.6x10-15N

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