A sequence begins with 8, 12, 16, 20, 24, 8, 12, 16, 20, 24, 8,… So, the sum of the first 48 terms of this sequence is___.Question 7Answera.500b.736c.720d.756

The given sequence is a repeating sequence of 8, 12, 16, 20, 24. This sequence repeats every 5 terms.

Step 1: Find the sum of the repeating sequence. 8 + 12 + 16 + 20 + 24 = 80

Step 2: Since the sequence repeats every 5 terms, divide the total number of terms by 5 to find out how many full sequences are in the 48 terms. 48 ÷ 5 = 9.6

Since we can't have a fraction of a sequence, we know that there are 9 full sequences and then a partial sequence in the 48 terms.

Step 3: Multiply the sum of the full sequence by the number of full sequences. 80 * 9 = 720

Step 4: Find the sum of the partial sequence. Since 0.6 of 5 is 3 (0.6 * 5 = 3), we know that the partial sequence is the first three terms of the sequence. 8 + 12 + 16 = 36

Step 5: Add the sum of the full sequences to the sum of the partial sequence. 720 + 36 = 756

So, the sum of the first 48 terms of this sequence is 756. Therefore, the answer is d. 756.