Gases A and B diffuse. If the rate of diffusion of A is 13cm3/s and the rate of diffusion B is 40cm3/s find the MM of B if A is 24g/mol
Question
Gases A and B diffuse. If the rate of diffusion of A is 13cm3/s and the rate of diffusion B is 40cm3/s find the MM of B if A is 24g/mol
Solution
The rate of diffusion of gases is inversely proportional to the square root of their molar masses. This relationship is described by Graham's law of diffusion:
Rate_A/Rate_B = sqrt(MM_B/MM_A)
Where: Rate_A = rate of diffusion of gas A Rate_B = rate of diffusion of gas B MM_A = molar mass of gas A MM_B = molar mass of gas B
Given: Rate_A = 13 cm^3/s Rate_B = 40 cm^3/s MM_A = 24 g/mol
We can substitute these values into Graham's law to find MM_B:
13/40 = sqrt(MM_B/24)
Solving for MM_B gives:
MM_B = (40/13)^2 * 24
MM_B = 70.9 g/mol
So, the molar mass of gas B is approximately 70.9 g/mol.
Similar Questions
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