If an ideal gas undergoes a process between two specified temperatures, first at constant pressure and then at constant volume, The entropy change will be ________Group of answer choiceslarger for constant volume processsamelarger for constant pressure processNext
Question
If an ideal gas undergoes a process between two specified temperatures, first at constant pressure and then at constant volume, The entropy change will be ________Group of answer choiceslarger for constant volume processsamelarger for constant pressure processNext
Solution
The entropy change will be larger for the constant pressure process.
Here's why:
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Entropy (S) is a measure of the randomness or disorder of a system. It is defined by the equation S = q/T, where q is the heat transferred during a process and T is the absolute temperature.
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For an ideal gas, the heat transferred during a constant pressure process (q_p) is greater than the heat transferred during a constant volume process (q_v). This is because at constant pressure, the gas is allowed to expand, doing work on its surroundings and absorbing more heat.
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Since q_p > q_v, and since the temperatures for the two processes are specified to be the same, it follows from the equation for entropy that the entropy change (ΔS = q/T) will be greater for the constant pressure process than for the constant volume process.
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