What will be the output of the program?class Test { public static void main(String [] args) { Test p = new Test(); p.start(); } void start() { boolean b1 = false; boolean b2 = fix(b1); System.out.println(b1 + " " + b2); } boolean fix(boolean b1) { b1 = true; return b1; }}true truefalse truetrue falsefalse false
Question
What will be the output of the program?class Test { public static void main(String [] args) { Test p = new Test(); p.start(); } void start() { boolean b1 = false; boolean b2 = fix(b1); System.out.println(b1 + " " + b2); } boolean fix(boolean b1) { b1 = true; return b1; }}true truefalse truetrue falsefalse false
Solution
The output of the program will be "false true".
Here's the step by step explanation:
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The main method is called, creating a new instance of the Test class and calling the start method.
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In the start method, b1 is initialized as false.
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b2 is assigned the value returned by the fix method, which is called with b1 as an argument.
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In the fix method, b1 is set to true and then returned. However, this does not affect the original b1 variable in the start method because Java is pass-by-value, meaning it passes a copy of the variable, not the original variable itself.
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Therefore, after the fix method is called, b1 remains false in the start method, but b2 is true because it was assigned the value returned by the fix method.
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Finally, the values of b1 and b2 are printed, resulting in "false true".
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