Which of the following shows the molar mass and amount, in mol, to the appropriate number of decimal places and/or significant figures for 7.84 g of CuSO4·5H2O?M(Cu)M(S)M(O)M(H)=63.55 g mol−1=32.07 g mol−1=16.00 g mol−1=1.01 g mol−1M(Cu)=63.55 g mol−1M(S)=32.07 g mol−1M(O)=16.00 g mol−1M(H)=1.01 g mol−1Molar mass (g mol−1) Amount in moles (mol)A 249.72 0.03B 250 0.0314C 250 0.03D 249.72 0.0314

First, we need to calculate the molar mass of CuSO4·5H2O.

The molar mass of CuSO4·5H2O is calculated as follows:

M(CuSO4·5H2O) = M(Cu) + M(S) + 4M(O) + 5(2*M(H) + M(O))

Substituting the given values:

M(CuSO4·5H2O) = 63.55 g/mol + 32.07 g/mol + 416.00 g/mol + 5(2*1.01 g/mol + 16.00 g/mol)

M(CuSO4·5H2O) = 63.55 g/mol + 32.07 g/mol + 64.00 g/mol + 5*(2.02 g/mol + 16.00 g/mol)

M(CuSO4·5H2O) = 63.55 g/mol + 32.07 g/mol + 64.00 g/mol + 5*18.02 g/mol

M(CuSO4·5H2O) = 159.62 g/mol + 90.10 g/mol

M(CuSO4·5H2O) = 249.72 g/mol

Next, we calculate the amount in moles using the formula:

n = m/M

where: n is the amount in moles, m is the mass, M is the molar mass.

Substituting the given values:

n = 7.84 g / 249.72 g/mol

n = 0.0314 mol

So, the correct answer is D: Molar mass = 249.72 g/mol, Amount in moles = 0.0314 mol.