The probability of an earthquake incident at a mine site in a single year is 0.41.Consider a par±cular mine site X where 64 employees work 12 hours/day, 283days/year in the pit and are therefore in the exposure zone of the incident. Forpeople in the exposure zone there is a 0.10 probability that an earthquakeincident will result in injury.What is the probability that there is injury from earthquake on that site in a year?
Question
The probability of an earthquake incident at a mine site in a single year is 0.41.Consider a par±cular mine site X where 64 employees work 12 hours/day, 283days/year in the pit and are therefore in the exposure zone of the incident. Forpeople in the exposure zone there is a 0.10 probability that an earthquakeincident will result in injury.What is the probability that there is injury from earthquake on that site in a year?
Solution
To solve this problem, we need to multiply the probability of each event happening, as they are independent events.
Step 1: The probability of an earthquake incident at a mine site in a single year is 0.41.
Step 2: The probability that an earthquake incident will result in injury for people in the exposure zone is 0.10.
Step 3: Multiply these two probabilities together to find the probability that there is an injury from an earthquake on that site in a year.
0.41 (probability of earthquake) * 0.10 (probability of injury given an earthquake) = 0.041 or 4.1%
So, the probability that there is an injury from an earthquake on that site in a year is 4.1%.
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