A power company calculates a person's monthly bill from the number of kilowatt-hours (kWh), x, used.The function 𝑏(𝑥)={0.15𝑥,𝑥≤2000.10(𝑥−200)+30,𝑥>200b(x)={ 0.15x,x≤2000.10(x−200)+30,x>200​ determines the bill.How much is the bill for a person who uses 300 kWh in a month?A.$55B.$40C.$60D.$45

Calculate the electricity bill amount for a month of 30 days, if the following devices are used as specified: a.two bulbs of 40W for six hours. } b.two tubelights of 50W for eight hours Kwh pa day c.A TV of 120W for six hours. d. Give the rate of electricity is 2.50 rupees per unit? 3

The local gas company uses the following function for computing their customers' monthly gas bills.C(x)={0.5x+8.839.35x−2646.17if0<x≤300ifx>300𝐶(𝑥)={0.5𝑥+8.83if0<𝑥≤3009.35𝑥−2646.17if𝑥>300, where x is the number of therms (thermal units) used and C(x)𝐶(𝑥) is the cost in dollars.Step 2 of 3 :  Find limx→300+C(x)lim𝑥→300+⁡𝐶(𝑥).

A phone company has a texting plan that charges a monthly rate based on the number of texts an individual sends per month.  This is modeled by the function cost of plan, 𝐶(𝑥),𝐶(𝑥), in dollars, is a function of the number of texts sent, 𝑥𝑥, per month.𝐶(𝑥)=⎧⎩⎨⎪⎪250.05𝑥+25.075𝑥+25 if 𝑥<100 if 100≤𝑥≤500 if 500<𝑥𝐶(𝑥)={25 if 𝑥<1000.05𝑥+25 if 100≤𝑥≤500.075𝑥+25 if 500<𝑥If you sent 500500 texts last month, what was the cost of your bill from the phone company? Question 2Answera.$37.50$37.50 b.$50.00$50.00c.$25.00$25.00d.$62.50

n Punjab, any person consuming energy has to pay a fixed charge and an additional amount proportional to the energy (in kilowatt (kwh)) consumed and if a person consumes more than 60 kwh per month, one has to pay an amount proportional to the square root of energy consumed (in kwh) in addition to the first additional amount. If a person pays ₹400 for 50 kwh, ₹360 for 30 kwh and ₹498 for 81 kwh, how much should he pay for 100 kwh (in ₹)?

The local water company uses the following function for computing their customers' monthly water bills.C(x)={1.09x+3.116.82x−4007.89if0<x≤700ifx>700𝐶(𝑥)={1.09𝑥+3.11if0<𝑥≤7006.82𝑥−4007.89if𝑥>700, where x is the number of gallons used and C(x)𝐶(𝑥) is the cost in dollars.Step 1 of 3 :  Find limx→700−C(x)lim𝑥→700−⁡𝐶(𝑥).