If an angle of a parallelogram is two-third of its adjacent angle, the smallest angle of the parallelogram is:a.81∘b.54∘c.108∘d.72∘
Question
If an angle of a parallelogram is two-third of its adjacent angle, the smallest angle of the parallelogram is:a.81∘b.54∘c.108∘d.72∘
Solution
In a parallelogram, adjacent angles are supplementary. This means that their sum is 180 degrees.
Let's denote the smaller angle as x. According to the problem, the larger angle is 2/3 times the smaller angle, so it can be represented as (2/3)x.
Since they are supplementary, we can set up the following equation:
x + (2/3)x = 180
Solving this equation will give us the value of the smaller angle, x.
First, combine like terms:
(1 + 2/3)x = 180
This simplifies to:
(5/3)x = 180
Next, to solve for x, divide both sides of the equation by 5/3, which is the same as multiplying by 3/5:
x = 180 * (3/5)
x = 108 degrees
So, the smallest angle of the parallelogram is 108 degrees, which corresponds to option c.
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