Here is a step-by-step solution to find the first non-repeating character in a string:

1. Initialize an empty dictionary. This will be used to store the frequency of each character in the string.

2. Iterate over the string. For each character, if it is already in the dictionary, increment its frequency by 1. If it is not in the dictionary, add it with a frequency of 1.

3. Iterate over the string a second time. For each character, check its frequency in the dictionary. If the frequency is 1, return this character as it is the first non-repeating character.

4. If no non-repeating character is found, return an appropriate message.

Here is a Python code snippet that implements the above steps:

```python
def find_first_non_repeating_char(s):
frequency = {}
for char in s:
if char in frequency:
frequency[char] += 1
else:
frequency[char] = 1

for char in s:
if frequency[char] == 1:
return char

return "No non-repeating character found"

print(find_first_non_repeating_char('swiss')) # Output: 'w'
```

In the given example, 'swiss', 'w' is the first character which does not repeat again in the word 'swiss'. Hence, the output is 'w'.

Question

Here is a step-by-step solution to find the first non-repeating character in a string:

1. Initialize an empty dictionary. This will be used to store the frequency of each character in the string.

2. Iterate over the string. For each character, if it is already in the dictionary, increment its frequency by 1. If it is not in the dictionary, add it with a frequency of 1.

3. Iterate over the string a second time. For each character, check its frequency in the dictionary. If the frequency is 1, return this character as it is the first non-repeating character.

4. If no non-repeating character is found, return an appropriate message.

Here is a Python code snippet that implements the above steps:

```python
def find_first_non_repeating_char(s):
    frequency = {}
    for char in s:
        if char in frequency:
            frequency[char] += 1
        else:
            frequency[char] = 1

for char in s:
        if frequency[char] == 1:
            return char

return "No non-repeating character found"

print(find_first_non_repeating_char('swiss'))  # Output: 'w'
```

In the given example, 'swiss', 'w' is the first character which does not repeat again in the word 'swiss'. Hence, the output is 'w'.

Knowee AI · Accepted Answer