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3(3x+2)=4(x−2)−5

Question

3(3x+2)=4(x−2)−5

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Solution

Sure, let's solve the equation step by step:

  1. Distribute the 3 on the left side of the equation and the 4 on the right side of the equation:

    9x + 6 = 4x - 8 - 5

  2. Simplify the right side of the equation:

    9x + 6 = 4x - 13

  3. Subtract 4x from both sides of the equation to get the x terms on one side:

    9x - 4x + 6 = 4x - 4x - 13

    Which simplifies to:

    5x + 6 = -13

  4. Subtract 6 from both sides of the equation to isolate the x term:

    5x + 6 - 6 = -13 - 6

    Which simplifies to:

    5x = -19

  5. Divide both sides of the equation by 5 to solve for x:

    x = -19/5

So, the solution to the equation 3(3x+2)=4(x−2)−5 is x = -19/5.

This problem has been solved

Similar Questions

3x-3\left(2-x\right)=4x+2\left(5-3x\right)

3(2 - x) - 5(x - 2) = x - 2(3 - x)

x−(5x+3)−3=−(−x+2)

(2x + 3)⁠(x − 5) = 0

Simplify the expression: 3(2x + 4) - 2(5 - x).

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