Given that the reaction,2 SO3(g) -> 2 SO2(g) + O2(g)has an enthalpy, (ΔH) of 198.2 kJ, What would be the enthalpy for the reverse reaction?Group of answer choices-198.2 kJ198.2 kJ

If you need to reverse the following reaction in order for it to be an intermediate reaction in a Hess's law problem, what would be the final value for the enthalpy of reaction you use for this intermediate reaction?H2 + 0.5 O2 H2O, H = -286 kJA.-286 kJB.286 kJC.572 kJD.-572 kJSUBMITarrow_backPREVIOUS

During a reaction, the enthalpy of formation of an intermediate is 90.3 kJ/mol. During the reaction, 2 moles of the intermediate are formed as a reactant. What is the enthalpy value for this step of the reaction?A.-90.3 kJB.90.3 kJC.180.6 kJD.-180.6 kJSUBMITarrow_backPREVIOUS

YouCalculate the heat released when 74.6 grams of SO2 reacts according to the following equation?2SO2+O2-->2SO3 deltaH=-99.1 kJ

The value of ΔH° for the reaction below is - 790 kJ.2S(s) + 3O2(g) → 2SO3(g)The enthalpy change accompanying the reaction of 0.95 g of S is ________kJ.Question 4Select one:a.23b.-23c.-12d.12e.-790

alculate the enthalpy of the following reaction: (3 marks)2Mg + O2 → 2MgOGiven:Mg + 2HCl → MgCl2 + H2 ΔH = -21.0 kJMgO + 2HCl → MgCl2 + H2O ΔH = -33.5 kJH2 + ½ O2 → H2O ΔH = -76.0 kJ