Concentration can be measured as:Grams/m3 or mol/m3Grams/cm3 or mol/cm3Grams/dm2 or mol/dm2Grams/dm3 or mol/dm32What is the concentration of 0.4 moles of sodium chloride dissolved in 2 dm3 of water?8 mol/dm32 mol/dm30.8 mol/dm30.2 mol/dm33What is the volume of 6 moles of 0.5 mol/dm3 sulfuric acid in cm3?3 cm312,000 cm312 cm33000 cm34How many moles of magnesium sulfate are dissolved in 5 dm3 of 0.5 mol/dm3 solution?0.5 moles2.5 moles5 moles0.25 moles
Question
Concentration can be measured as:Grams/m3 or mol/m3Grams/cm3 or mol/cm3Grams/dm2 or mol/dm2Grams/dm3 or mol/dm32What is the concentration of 0.4 moles of sodium chloride dissolved in 2 dm3 of water?8 mol/dm32 mol/dm30.8 mol/dm30.2 mol/dm33What is the volume of 6 moles of 0.5 mol/dm3 sulfuric acid in cm3?3 cm312,000 cm312 cm33000 cm34How many moles of magnesium sulfate are dissolved in 5 dm3 of 0.5 mol/dm3 solution?0.5 moles2.5 moles5 moles0.25 moles
Solution
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The concentration of a solution is calculated by dividing the amount of solute (in moles) by the volume of the solution (in dm3). So, for 0.4 moles of sodium chloride dissolved in 2 dm3 of water, the concentration would be 0.4 moles / 2 dm3 = 0.2 mol/dm3.
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The volume of a solution can be calculated by dividing the amount of solute (in moles) by the concentration of the solution (in mol/dm3). So, for 6 moles of 0.5 mol/dm3 sulfuric acid, the volume would be 6 moles / 0.5 mol/dm3 = 12 dm3. Since 1 dm3 = 1000 cm3, the volume would be 12,000 cm3.
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The amount of solute in a solution can be calculated by multiplying the volume of the solution (in dm3) by the concentration of the solution (in mol/dm3). So, for 5 dm3 of 0.5 mol/dm3 magnesium sulfate solution, the amount of magnesium sulfate would be 5 dm3 * 0.5 mol/dm3 = 2.5 moles.
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