The problem is asking to find the longest subarray from the given array where the absolute difference between any two elements is less than or equal to 1.

Here are the steps to solve this problem:

1. First, sort the array in ascending order. This will make it easier to compare the differences between adjacent elements.

2. Initialize a counter and a max_counter to keep track of the length of the current subarray and the length of the longest subarray found so far, respectively.

3. Iterate over the array. For each element, compare it with the next element. If the absolute difference is less than or equal to 1, increment the counter. If the difference is greater than 1, compare the counter with the max_counter and update the max_counter if necessary, then reset the counter to 1.

4. After the loop, do one final comparison between the counter and the max_counter to account for the possibility that the longest subarray ends at the last element of the array.

5. Return the max_counter as the length of the longest subarray that meets the criterion.

In Python, the function could look like this:

```python
def pickingNumbers(a):
a.sort()
counter = 1
max_counter = 1
for i in range(len(a) - 1):
if abs(a[i] - a[i+1])

Question

The problem is asking to find the longest subarray from the given array where the absolute difference between any two elements is less than or equal to 1.

Here are the steps to solve this problem:

1. First, sort the array in ascending order. This will make it easier to compare the differences between adjacent elements.

2. Initialize a counter and a max_counter to keep track of the length of the current subarray and the length of the longest subarray found so far, respectively.

3. Iterate over the array. For each element, compare it with the next element. If the absolute difference is less than or equal to 1, increment the counter. If the difference is greater than 1, compare the counter with the max_counter and update the max_counter if necessary, then reset the counter to 1.

4. After the loop, do one final comparison between the counter and the max_counter to account for the possibility that the longest subarray ends at the last element of the array.

5. Return the max_counter as the length of the longest subarray that meets the criterion.

In Python, the function could look like this:

```python
def pickingNumbers(a):
    a.sort()
    counter = 1
    max_counter = 1
    for i in range(len(a) - 1):
        if abs(a[i] - a[i+1]) <= 1:
            counter += 1
        else:
            max_counter = max(max_counter, counter)
            counter = 1
    max_counter = max(max_counter, counter)
    return max_counter
```

This function sorts the array, then iterates over it, comparing each element with the next one and updating the counters as necessary. It returns the length of the longest subarray where

Knowee AI · Accepted Answer