Suppose the formation of iodine proceeds by the following mechanism:step elementary reaction rate constant1 H2(g) + ICl(g) → HI(g) + HCl(g) k12 HI(g) + ICl(g) → I2(g) + HCl(g) k2Suppose also k1≫k2. That is, the first step is much faster than the second.Write the balanced chemical equation for the overall chemical reaction: Write the experimentally-observable rate law for the overall chemical reaction. =ratek Note: your answer should not contain the concentrations of any intermediates.Express the rate constant k for the overall chemical reaction in terms of k1, k2, and (if necessary) the rate constants k-1 and k-2 for the reverse of the two elementary reactions in the mechanism. =k
Question
Suppose the formation of iodine proceeds by the following mechanism:step elementary reaction rate constant1 H2(g) + ICl(g) → HI(g) + HCl(g) k12 HI(g) + ICl(g) → I2(g) + HCl(g) k2Suppose also k1≫k2. That is, the first step is much faster than the second.Write the balanced chemical equation for the overall chemical reaction: Write the experimentally-observable rate law for the overall chemical reaction. =ratek Note: your answer should not contain the concentrations of any intermediates.Express the rate constant k for the overall chemical reaction in terms of k1, k2, and (if necessary) the rate constants k-1 and k-2 for the reverse of the two elementary reactions in the mechanism. =k
Solution
The balanced chemical equation for the overall chemical reaction is:
H2(g) + 2ICl(g) → I2(g) + 2HCl(g)
The experimentally-observable rate law for the overall chemical reaction is:
rate = k[H2][ICl]^2
The rate constant k for the overall chemical reaction in terms of k1, k2, and (if necessary) the rate constants k-1 and k-2 for the reverse of the two elementary reactions in the mechanism is:
k = k1 * k2 / (k1 + k2)
Note: This is under the assumption that the first step is in equilibrium, which is reasonable given that k1 is much larger than k2.
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