Find the equation of the directrix of the parabola y² = 16x.
Question
Find the equation of the directrix of the parabola y² = 16x.
Solution
The equation of a parabola in the form y² = 4ax opens to the right if a is positive and to the left if a is negative. The directrix of such a parabola is a vertical line x = -a.
Given the equation of the parabola y² = 16x, we can compare it to the standard form y² = 4ax to find the value of a. Here, 4a = 16, so a = 4.
Therefore, the equation of the directrix of the parabola y² = 16x is x = -a, which simplifies to x = -4.
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