The sum of the ages of a father and his son is 45 years. If 5 years ago, the father was 4 times as old as his son, what is the present age of the son?a.9b.11c.7d.5
Question
The sum of the ages of a father and his son is 45 years. If 5 years ago, the father was 4 times as old as his son, what is the present age of the son?a.9b.11c.7d.5
Solution
Let's denote the present age of the father as F and the present age of the son as S.
From the problem, we know that:
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F + S = 45 (the sum of their present ages is 45)
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F - 5 = 4 * (S - 5) (five years ago, the father was four times as old as the son)
We can solve these equations step by step:
Step 1: Rewrite the second equation as F = 4S - 15
Step 2: Substitute F from the first equation into the second equation: 4S - 15 + S = 45
Step 3: Simplify the equation: 5S - 15 = 45
Step 4: Add 15 to both sides of the equation: 5S = 60
Step 5: Divide both sides of the equation by 5: S = 12
So, the present age of the son is 12 years old. However, this option is not listed in the choices. There might be a mistake in the problem or the choices.
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