Shape A is a regular polygon with 18 sidesShape B is a regular polygon with 24 sidesWhat is the size of angle y?

To find the size of angle y in each of the given regular polygons, we need to determine the measure of the interior angles of each polygon.

1. Shape A (18-sided polygon):

   • The formula to find the measure of an interior angle of a regular polygon is: $\text{Interior Angle} = \frac{(n-2) \times 180^\circ}{n}$ where $n$ is the number of sides.
   • For Shape A, $n = 18$: $\text{Interior Angle of Shape A} = \frac{(18-2) \times 180^\circ}{18} = \frac{16 \times 180^\circ}{18} = \frac{2880^\circ}{18} = 160^\circ$

2. Shape B (24-sided polygon):

   • Using the same formula for Shape B, where $n = 24$: $\text{Interior Angle of Shape B} = \frac{(24-2) \times 180^\circ}{24} = \frac{22 \times 180^\circ}{24} = \frac{3960^\circ}{24} = 165^\circ$

Therefore, the size of angle y in Shape A is $160^\circ$ and in Shape B is $165^\circ$.