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Right triangle ABC is located at A (−1, −2), B (−1, 1), and C (−5, 1) on a coordinate plane. What is the equation of a circle A with radius ?Group of answer choices(x + 1)2 + (y + 2)2 = 9(x + 5)2 + (y − 1)2 = 16(x + 1)2 + (y + 2)2 = 25(x + 5)2 + (y − 1)2 = 25

Question

Right triangle ABC is located at A (−1, −2), B (−1, 1), and C (−5, 1) on a coordinate plane. What is the equation of a circle A with radius ?Group of answer choices(x + 1)2 + (y + 2)2 = 9(x + 5)2 + (y − 1)2 = 16(x + 1)2 + (y + 2)2 = 25(x + 5)2 + (y − 1)2 = 25

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Solution

The equation of a circle is given by (x - h)² + (y - k)² = r², where (h, k) is the center of the circle and r is the radius.

From the given points, we can see that point A (-1, -2) is the center of the circle. The radius is not given, but we can calculate it using the distance formula between two points, which is √[(x₂ - x₁)² + (y₂ - y₁)²].

Let's calculate the distance between point A and point B to get the radius:

r = √[(-1 - (-1))² + (-2 - 1)²] = √[0 + 9] = 3

So, the equation of the circle is (x + 1)² + (y + 2)² = 3², which simplifies to (x + 1)² + (y + 2)² = 9.

Therefore, the correct answer is (x + 1)² + (y + 2)² = 9.

This problem has been solved

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