The components of a force can be found using trigonometric functions. The x-component (Fx) is found by multiplying the force by the cosine of the angle, and the y-component (Fy) is found by multiplying the force by the sine of the angle.

Given that the force (F) is 5N and the angle (θ) is 65 degrees west of north, we can find the components as follows:

First, we need to convert the angle to standard position. In standard position, angles are measured counter-clockwise from the positive x-axis. So, 65 degrees west of north is equivalent to 90 + 65 = 155 degrees in standard position.

Next, we calculate the components:

Fx = F * cos(θ) = 5N * cos(155 degrees) = -4.53 N
Fy = F * sin(θ) = 5N * sin(155 degrees) = 2.11 N

So, the components of the force are Fx = -4.53 N and Fy = 2.11 N.

Question

The components of a force can be found using trigonometric functions. The x-component (Fx) is found by multiplying the force by the cosine of the angle, and the y-component (Fy) is found by multiplying the force by the sine of the angle.

Given that the force (F) is 5N and the angle (θ) is 65 degrees west of north, we can find the components as follows:

First, we need to convert the angle to standard position. In standard position, angles are measured counter-clockwise from the positive x-axis. So, 65 degrees west of north is equivalent to 90 + 65 = 155 degrees in standard position.

Next, we calculate the components:

Fx = F * cos(θ) = 5N * cos(155 degrees) = -4.53 N
Fy = F * sin(θ) = 5N * sin(155 degrees) = 2.11 N

So, the components of the force are Fx = -4.53 N and Fy = 2.11 N.

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The components of a force can be found using trigonometric functions. The x-component (Fx) is found by multiplying the force by the cosine of the angle, and the y-component (Fy) is found by multiplying the force by the sine of the angle.

Given that the force (F) is 5N and the angle (θ) is 65 degrees west of north, we can find the components as follows:

First, we need to convert the angle to standard position. In standard position, angles are measured counter-clockwise from the positive x-axis. So, 65 degrees west of north is equivalent to 90 + 65 = 155 degrees in standard position.

Next, we calculate the components:

Fx = F * cos(θ) = 5N * cos(155 degrees) = -4.53 N
Fy = F * sin(θ) = 5N * sin(155 degrees) = 2.11 N

So, the components of the force are Fx = -4.53 N and Fy = 2.11 N.

What are the components of the given force, F = 5N, 65o West of NorthGroup of answer choicesFx = -4.53 N , Fy = -2.11 NFx = - 4.53 N , Fy = 2.11 NFx = 4.53 N , Fy = -2.11 NFx = 2.11 N , Fy = 4.53 N

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