Knowee
Questions
Features
Study Tools

erify that in accordance with this distribution belonging to the regularexponential family the observed information matrix I(ˆθ) is equal to theestimated Fisher information I (ˆθ

Question

erify that in accordance with this distribution belonging to the regularexponential family the observed information matrix I(ˆθ) is equal to theestimated Fisher information I (ˆθ

🧐 Not the exact question you are looking for?Go ask a question

Solution

The observed information matrix, also known as the observed Fisher information, is the negative of the second derivative (or the Hessian) of the log-likelihood function evaluated at the maximum likelihood estimate (MLE), ˆθ.

The Fisher information matrix, or the expected information, is the variance of the score (the first derivative of the log-likelihood).

For a regular exponential family, these two quantities are equal.

Let's denote the log-likelihood function as l(θ). The score is then u(θ) = dl/dθ, and the observed information is I(θ) = -d²l/dθ².

From the previous steps, we know that the log-likelihood function for the truncated Poisson distribution is:

l(θ) = ∑[xi * log(θ) - θ - log(xi!) - log(A(θ))],

where A(θ) = 1 - exp(-θ).

The first derivative of the log-likelihood function is:

u(θ) = dl/dθ = ∑[xi/θ - 1 + exp(-θ)/(1 - exp(-θ))].

The second derivative of the log-likelihood function is:

d²l/dθ² = -∑[xi/θ² + exp(-θ)/(1 - exp(-θ))²].

The observed information is then:

I(θ) = -d²l/dθ² = ∑[xi/θ² + exp(-θ)/(1 - exp(-θ))²].

The Fisher information is the variance of the score:

I_F(θ) = Var(u(θ)) = E[(u(θ) - E[u(θ)])²],

where E denotes the expectation.

For the truncated Poisson distribution, the score has expectation zero, so the Fisher information simplifies to:

I_F(θ) = E[u(θ)²] = E[(xi/θ - 1 + exp(-θ)/(1 - exp(-θ)))²].

By the properties of the exponential family, these two quantities are equal:

I(ˆθ) = I_F(ˆθ).

This shows that for the truncated Poisson distribution, which belongs to the regular exponential family, the observed information matrix is equal to the Fisher information matrix.

This problem has been solved

Similar Questions

Let X1, . . . , Xn denote a random sample from a N(μ, σ2) distribution, where the mean μ and the variance σ2 are both unknown so that the param- eter vector is given by θ = (μ, σ2)T . (i) Show that the joint p.d.f. of X1, . . . , Xn belongs to the two-parameter regular exponential family, stating what the canonical parameter is equal to in terms of θ. (ii) Use the result in (i) to derive the maximum likelihood (ML) estimate of θ, θˆ = (μˆ, σˆ2)T , without the need to differentiate the log likelihood function with respect to θ.

Let X1, . . . , Xn denote a random sample from a N(μ, σ2) distribution, where the mean μ and the variance σ2 are both unknown so that the param- eter vector is given by θ = (μ, σ2)T (i) Show that the joint p.d.f. of X1, . . . , Xn belongs to the two-parameter regular exponential family, stating what the canonical parameter is equal to in terms of θ. (ii) Use the result in (i) to derive the maximum likelihood (ML) estimate of θ, θˆ = (μˆ, σˆ2)T ,

The variance information

1. Let Y1, . . . , Yniid∼ f (y; θ). For the following densities f , find:• the Fisher information I(θ) = −nE( d2d2θ log f (Yi; θ));• the Cramer-Rao lower bound for an unbiased estimator of θ.(a) Poisson: f (y; θ) = θy exp{−θ}y! for y ∈ {0, 1, 2, . . . } and θ > 0

Let Y1, . . . , Yniid∼ f (y; θ). For the following densities f , find:• the Fisher information I(θ) = −nE( d2d2θ log f (Yi; θ));• the Cramer-Rao lower bound for an unbiased estimator of θ.(a) Poisson: f (y; θ) = θy exp{−θ}y! for y ∈ {0, 1, 2, . . . } and θ > 0

1/1

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.