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Ammonia is commonly produced via the Haber-Bosch process, which proceeds via the following equilibrium:𝑁2+3𝐻2⇌2𝑁𝐻3The reaction has reached equilibrium. The concentration of nitrogen is 1.41 M, The concentration of hydrogen is 2.43 M and the concentration of ammonia is 4.67 M. What is the value of the equilibrium constant, Kc to 2 decimal places?

Question

Ammonia is commonly produced via the Haber-Bosch process, which proceeds via the following equilibrium:𝑁2+3𝐻2⇌2𝑁𝐻3The reaction has reached equilibrium. The concentration of nitrogen is 1.41 M, The concentration of hydrogen is 2.43 M and the concentration of ammonia is 4.67 M. What is the value of the equilibrium constant, Kc to 2 decimal places?

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Solution

The equilibrium constant, Kc, for a reaction is given by the formula:

Kc = [Products] / [Reactants]

In the Haber-Bosch process, the reaction is: N2 + 3H2 ⇌ 2NH3

So, the equilibrium constant Kc is given by:

Kc = ([NH3]^2) / ([N2] * [H2]^3)

Given that the concentration of nitrogen (N2) is 1.41 M, the concentration of hydrogen (H2) is 2.43 M, and the concentration of ammonia (NH3) is 4.67 M, we can substitute these values into the formula:

Kc = (4.67^2) / (1.41 * 2.43^3)

Now, calculate the values:

Kc = 21.81 / (1.41 * 14.35)

Kc = 21.81 / 20.23

Kc = 1.08

So, the value of the equilibrium constant, Kc, to 2 decimal places is 1.08.

This problem has been solved

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