Let's use a system of equations to find the cost of each shirt (s) and each tie (t) in dollars.

Let's assume that the cost of each shirt is s dollars and the cost of each tie is t dollars.

From the given information, we can set up the following equations:

Equation 1: 4s + 2t = 95 (Ted bought 4 shirts and 2 ties for a total price of $95)
Equation 2: 3s + 3t = 84 (Stephen bought 3 shirts and 3 ties for $84)

These two equations represent the total cost of shirts and ties purchased by Ted and Stephen.

Now, we can solve this system of equations to find the values of s and t.

To do this, we can use the method of substitution or elimination.

Let's use the method of elimination to solve this system of equations.

First, let's multiply Equation 1 by 3 and Equation 2 by 2 to make the coefficients of s in both equations the same:

Equation 1: 12s + 6t = 285
Equation 2: 6s + 6t = 168

Now, subtract Equation 2 from Equation 1:

(12s + 6t) - (6s + 6t) = 285 - 168

This simplifies to:

6s = 117

Divide both sides of the equation by 6:

s = 19.5

Now, substitute the value of s back into either Equation 1 or Equation 2 to find the value of t.

Let's substitute s = 19.5 into Equation 1:

4(19.5) + 2t = 95

78 + 2t = 95

Subtract 78 from both sides of the equation:

2t = 17

Divide both sides of the equation by 2:

t = 8.5

Therefore, the cost of each shirt (s) is $19.5 and the cost of each tie (t) is $8.5.

The system of equations that can be used to find s and t is:

Equation 1: 4s + 2t = 95
Equation 2: 3s + 3t = 84

Question

Let's use a system of equations to find the cost of each shirt (s) and each tie (t) in dollars.

Let's assume that the cost of each shirt is s dollars and the cost of each tie is t dollars.

From the given information, we can set up the following equations:

Equation 1: 4s + 2t = 95 (Ted bought 4 shirts and 2 ties for a total price of $95)
Equation 2: 3s + 3t = 84 (Stephen bought 3 shirts and 3 ties for $84)

These two equations represent the total cost of shirts and ties purchased by Ted and Stephen.

Now, we can solve this system of equations to find the values of s and t.

To do this, we can use the method of substitution or elimination.

Let's use the method of elimination to solve this system of equations.

First, let's multiply Equation 1 by 3 and Equation 2 by 2 to make the coefficients of s in both equations the same:

Equation 1: 12s + 6t = 285
Equation 2: 6s + 6t = 168

Now, subtract Equation 2 from Equation 1:

(12s + 6t) - (6s + 6t) = 285 - 168

This simplifies to:

6s = 117

Divide both sides of the equation by 6:

s = 19.5

Now, substitute the value of s back into either Equation 1 or Equation 2 to find the value of t.

Let's substitute s = 19.5 into Equation 1:

4(19.5) + 2t = 95

78 + 2t = 95

Subtract 78 from both sides of the equation:

2t = 17

Divide both sides of the equation by 2:

t = 8.5

Therefore, the cost of each shirt (s) is $19.5 and the cost of each tie (t) is $8.5.

The system of equations that can be used to find s and t is:

Equation 1: 4s + 2t = 95
Equation 2: 3s + 3t = 84

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