The code provided is written in TypeScript, a statically typed superset of JavaScript. It defines a function `sum` that takes two arguments, `data1` and `data2`. `data2` is an optional parameter. If `data2` is provided, the function adds `data1`, `data2`, and `data3` (which is always 10) together. If `data2` is not provided, the function attempts to add `data1` and `data3` together.

However, there is an error in the code. The variable `data3` is defined inside the `if` block, which means it is not accessible in the `else` block. Therefore, the line `return data1 + data3;` in the `else` block will throw an error because `data3` is not defined in that scope.

Assuming that the error is fixed by moving the definition of `data3` outside the `if` block, the function calls would return the following:

`sum(5)` would return `15` because `data1` is `5` and `data3` is `10`, and `data2` is not provided.

`sum(10,15)` would return `35` because `data1` is `10`, `data2` is `15`, and `data3` is `10`.

Therefore, the correct answer is `35, 15`.

Question

The code provided is written in TypeScript, a statically typed superset of JavaScript. It defines a function `sum` that takes two arguments, `data1` and `data2`. `data2` is an optional parameter. If `data2` is provided, the function adds `data1`, `data2`, and `data3` (which is always 10) together. If `data2` is not provided, the function attempts to add `data1` and `data3` together.

However, there is an error in the code. The variable `data3` is defined inside the `if` block, which means it is not accessible in the `else` block. Therefore, the line `return data1 + data3;` in the `else` block will throw an error because `data3` is not defined in that scope.

Assuming that the error is fixed by moving the definition of `data3` outside the `if` block, the function calls would return the following:

`sum(5)` would return `15` because `data1` is `5` and `data3` is `10`, and `data2` is not provided.

`sum(10,15)` would return `35` because `data1` is `10`, `data2` is `15`, and `data3` is `10`.

Therefore, the correct answer is `35, 15`.

Knowee AI · Accepted Answer

The code provided is written in TypeScript, a statically typed superset of JavaScript. It defines a function `sum` that takes two arguments, `data1` and `data2`. `data2` is an optional parameter. If `data2` is provided, the function adds `data1`, `data2`, and `data3` (which is always 10) together. If `data2` is not provided, the function attempts to add `data1` and `data3` together.

However, there is an error in the code. The variable `data3` is defined inside the `if` block, which means it is not accessible in the `else` block. Therefore, the line `return data1 + data3;` in the `else` block will throw an error because `data3` is not defined in that scope.

Assuming that the error is fixed by moving the definition of `data3` outside the `if` block, the function calls would return the following:

`sum(5)` would return `15` because `data1` is `5` and `data3` is `10`, and `data2` is not provided.

`sum(10,15)` would return `35` because `data1` is `10`, `data2` is `15`, and `data3` is `10`.

Therefore, the correct answer is `35, 15`.

function sum(data1: number, data2?: number) { if(data2){ const data3: number = 10; return data1 + data2 + data3; } else { return data1 + data3; }}const myAnswer1: number = sum(5);const myAnswer2: number = sum(10,15);console.log(myAnswer2);console.log(myAnswer1);*1 point15, 3535, 15

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