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In a full binary tree if number of internal nodes is I, then number of leaves L are?OptionsL = 2*IL = I + 1 L = I – 1L = 2*I – 1

Question

In a full binary tree if number of internal nodes is I, then number of leaves L are?OptionsL = 2IL = I + 1 L = I – 1L = 2I – 1

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Solution

The number of leaves L in a full binary tree, where the number of internal nodes is I, is given by the formula L = I + 1.

Here's why:

In a full binary tree, every internal node has exactly two children. Therefore, the number of edges leading to leaves is twice the number of internal nodes. However, since each leaf is connected by one edge, the number of leaves is equal to the number of internal nodes plus one.

So, the correct option is L = I + 1.

This problem has been solved

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