4. Consider the reaction:N2(g) + O2(g) → 2NO(g) ΔHo = 180.5 kJIf 124 kJ of heat is absorbed in a reaction that forms nitric oxide from nitrogen and oxygen, what mass of NO must have been produced? What mass of N2 was consumed?5. Using these reactions, find the standard enthalpy change for the formation of 1 mol PbO(s) from lead metal and oxygen gas. If250. g of lead reacts with oxygen to form lead(II) oxide, what quantity of thermal energy (in kJ) is absorbed or evolved?

The standard enthalpy of formation of gaseous nitrogen dioxide is 33.2 kJ/mol, liquid water is -285.8 kJ/mol, aqueous nitric acid is -207 kJ/mol and the standard enthalpy of formation of gaseous nitrogen monoxide is 91.3 kJ/mol . Calculate the ΔHorxn for the following reaction:   3NO2(g) +  H2O(l)   →   2 HNO3(aq) + NO(g)

alculate the standard free energy change at 25°C for the reaction2 NO(g) + O2(g) → 2 NO2(g).Group of answer choices-532.6 kJ-157.8 kJ-4.7 kJ-72.6 kJ

Calculate ΔrG(in kJ/mol) for given reaction at 300 KN2(g) + O2(g) ⇌ 2NO(g)the partial pressure of N2, O2 & NO are 10–4 bar, 10–2 bar and 10–5 bar respectively when mixed together at 300 K.Given : 2.303 RT = 5750 J/molAt 300 K standard enthalpy of formation of NO(g) = 90.5 kJ mol–1,Standard molar entropy data at 300 K :S°(N2, g) = 190 J K–1 mol–1S°(NO, g) = 210 J K–1 mol–1S°(O2,g) = 205 J K–1 mol–1 ?

(ii) Show that the heat energy change, Q, in the student’s experiment is about 1100 J.[for the mixture, c = 4.2 J/g/°C][massof1.0 cm 3of mixture = 1.0 g] (3)(iii) The student uses 0.020 mol of potassium hydroxide in his experiment.Calculate the enthalpy change (ΔH) in kJ/mol, for 1.0 mol of potassium hydroxide.Include a sign in your answer.

Given the following enthalpies of formation in kJ/mol:CH4(g) = - 74.8           O3(g) = 143H2O(g) = - 242             CO2(g) = - 394what is the standard heat of reaction in kJ/mol for the reaction below?3 CH4(g) + 4 O3(g) 3 CO2(g) + 6 H2O(g)Question 6Select one:a.(3 x -394   +  6 x -242)   +   ( 3 x -74.8  +   4 x 143) b.(3 x -394   +  6 x -242)   -   ( 3 x 74.8  +   4 x  -143) c.(3 x -394   +  6 x -242)   -   ( 3 x -74.8  +   4 x 143) d.( 3 x -74.8  +   4 x  143)  -  (3 x -394   +  6 x -242)e.( 3 x -74.8  +   4 x  143)  +  (3 x -394   +  6 x -242)