Oxidation state of Benedict reagent
Question
Oxidation state of Benedict reagent
Solution
Benedict's reagent is a chemical reagent named after an American chemist, Stanley Rossiter Benedict. This reagent is used as a test for the presence of reducing sugars (all monosaccharides and some disaccharides), including glucose and fructose.
Benedict's reagent consists of blue copper(II) sulfate (CuSO4), sodium citrate, and sodium carbonate. The copper(II) sulfate provides Cu2+ ions, which have an oxidation state of +2.
When Benedict's reagent is mixed with a solution containing reducing sugars and heated, the solution changes color. The Cu2+ ions are reduced to Cu+ ions (copper(I) oxide), which have an oxidation state of +1. This reduction reaction is what causes the color change, as copper(I) oxide is red or green, depending on the concentration of reducing sugar in the solution.
So, the oxidation state of the copper in Benedict's reagent changes from +2 to +1 during the reaction with reducing sugars.
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