Write the sum using sigma notation.2 + 4 + 6 +    + 58 k = 1

The sum 2 + 4 + 6 + ... + 58 can be written in sigma notation as follows:

Σ_{k=1}^{29} 2k

Here's the step-by-step explanation:

1. Identify the common difference between consecutive terms. In this case, the common difference is 2.

2. The general term that generates the sequence is 2k, where k is the term number.

3. The first term corresponds to k=1.

4. The last term, 58, corresponds to k=29 because 2*29=58.

5. Therefore, the sum can be written as the sum from k=1 to k=29 of 2k.