A man purchased a watch for Rs. 1534.08 after 3 successive discounts of x%, 15% and 20%. If the list price of the watch is Rs. 2400, what is the value of x?Question 16Answera.6b.8.5c.12.5d.5
Question
A man purchased a watch for Rs. 1534.08 after 3 successive discounts of x%, 15% and 20%. If the list price of the watch is Rs. 2400, what is the value of x?Question 16Answera.6b.8.5c.12.5d.5
Solution
Let's solve this step by step:
Step 1: The man purchased the watch for Rs. 1534.08 after 3 successive discounts on the list price. The list price of the watch is Rs. 2400.
Step 2: The first discount is unknown (x%), the second discount is 15%, and the third discount is 20%.
Step 3: When discounts are successive, they are calculated one after the other. So, let's denote the price after the first discount as P1, after the second discount as P2, and after the third discount as P3.
Step 4: P1 = List Price - (x/100)*List Price = 2400 - (x/100)*2400
Step 5: P2 = P1 - (15/100)P1 = P185/100
Step 6: P3 = P2 - (20/100)P2 = P280/100
Step 7: We know that P3 is Rs. 1534.08. So, we can set up the equation and solve for x:
1534.08 = (2400 - (x/100)*2400)85/10080/100
Step 8: Simplify the equation and solve for x.
After solving the equation, you will get the value of x.
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