A pendulum of length 1m and period 2.01s is placed at the top of MountEveresthaving an altitude of 8849m. Calculate the value of ‘g’ at that point.

Calculate the frequency of a simple pendulum, if its length is 50 cm.(Note: The acceleration due to gravity ‘g’ is 9.8 m/s2.

If the period of oscillation of a simple pendulum is 4s, find its length. If the velocity of the bobat the mean position is 40cms−1, find its amplitude. (take gravity = 9.81ms−2)

a) The period of a simple pendulum is T = 2𝜋L/g where L is the length of the pendulum and g is the acceleration due to gravity at the pendulum's location. Thus, if a pendulum has a period of T = 1.9 s on Earth where gEarth = 9.8 m/s2, its length isLEarth  =  gEarthT24𝜋2    =  m/s2 s 2 4𝜋2    =  m = cm

A pendulum clock has a period of 1.0 s and gives the correct time on the ground at acertain location. It is then moved to the top of a building that is 320 m high. How muchtime will the pendulum lose in 1 day at this height?a. 2.25 s b. 2.88 s c. 3.42 s d. 3.94 s e. 4.32

A simple pendulum has a period of 3.65 s on the surface of the Earth. If this pendulum were placed on the surface of the Moon, where the gravitational acceleration is 1.62 m/s2m/s2 , what would its period be?