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There are two college entrance exams that are often taken by​ students, Exam A and Exam B. The composite score on Exam A is approximately normally distributed with mean 20.7 and standard deviation 5.1. The composite score on Exam B is approximately normally distributed with mean 1036 and standard deviation 214. Suppose you scored 25 on Exam A and 1182 on Exam B.a) What is the z-score of Exam A?

Question

There are two college entrance exams that are often taken by​ students, Exam A and Exam B. The composite score on Exam A is approximately normally distributed with mean 20.7 and standard deviation 5.1. The composite score on Exam B is approximately normally distributed with mean 1036 and standard deviation 214. Suppose you scored 25 on Exam A and 1182 on Exam B.a) What is the z-score of Exam A?

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Solution

The z-score is a measure of how many standard deviations an element is from the mean. To calculate the z-score for the Exam A score, you would use the following formula:

z = (X - μ) / σ

where:

  • X is the score from the exam,
  • μ is the mean score, and
  • σ is the standard deviation.

For Exam A:

  • X = 25 (your score)
  • μ = 20.7 (the mean)
  • σ = 5.1 (the standard deviation)

Substituting these values into the formula gives:

z = (25 - 20.7) / 5.1

This simplifies to:

z = 4.3 / 5.1

So, the z-score for your Exam A score is approximately 0.843. This means your score was approximately 0.843 standard deviations above the mean.

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