(a) To find out how long it takes for the ball to hit the ground, we can use the equation of motion:

h = 0.5gt^2

where:
h = height = 10.0 m
g = acceleration due to gravity = 9.8 m/s^2
t = time

Rearranging the equation to solve for t gives:

t = sqrt((2h)/g)

Substituting the given values:

t = sqrt((2*10.0 m)/(9.8 m/s^2)) = 1.43 seconds

So, it takes approximately 1.43 seconds for the ball to hit the ground.

(b) To find the final velocity of the ball just before it hits the ground, we can use the equation:

v = gt

where:
v = final velocity
g = acceleration due to gravity = 9.8 m/s^2
t = time = 1.43 seconds

Substituting the given values:

v = 9.8 m/s^2 * 1.43 seconds = 14.0 m/s

So, the final velocity of the ball just before it hits the ground is approximately 14.0 m/s.

Question

(a) To find out how long it takes for the ball to hit the ground, we can use the equation of motion:

h = 0.5gt^2

where:
h = height = 10.0 m
g = acceleration due to gravity = 9.8 m/s^2
t = time

Rearranging the equation to solve for t gives:

t = sqrt((2h)/g)

Substituting the given values:

t = sqrt((2*10.0 m)/(9.8 m/s^2)) = 1.43 seconds

So, it takes approximately 1.43 seconds for the ball to hit the ground.

(b) To find the final velocity of the ball just before it hits the ground, we can use the equation:

v = gt

where:
v = final velocity
g = acceleration due to gravity = 9.8 m/s^2
t = time = 1.43 seconds

Substituting the given values:

v = 9.8 m/s^2 * 1.43 seconds = 14.0 m/s

So, the final velocity of the ball just before it hits the ground is approximately 14.0 m/s.

Knowee AI · Accepted Answer

(a) To find out how long it takes for the ball to hit the ground, we can use the equation of motion:

h = 0.5gt^2

where:
h = height = 10.0 m
g = acceleration due to gravity = 9.8 m/s^2
t = time

Rearranging the equation to solve for t gives:

t = sqrt((2h)/g)

Substituting the given values:

t = sqrt((2*10.0 m)/(9.8 m/s^2)) = 1.43 seconds

So, it takes approximately 1.43 seconds for the ball to hit the ground.

(b) To find the final velocity of the ball just before it hits the ground, we can use the equation:

v = gt

where:
v = final velocity
g = acceleration due to gravity = 9.8 m/s^2
t = time = 1.43 seconds

Substituting the given values:

v = 9.8 m/s^2 * 1.43 seconds = 14.0 m/s

So, the final velocity of the ball just before it hits the ground is approximately 14.0 m/s.

Students performing an experiment for their physicsclass are dropping balls from a height of 10.0 m.Ignore air resistance. (1.6) T/I(a) How long does it take for a ball to hit the ground?(b) What is the final velocity of the ball just before ithits the ground?