Salt water with density of 0.25 g/cm2 flows over the curve r(t) = t0.5 i + t j, 0 ≤ t ≤ 4,according to the vector field F = 0.25v where v = xy i + (y-x) j is the velocity fieldmeasured in cm/s. Find the flow of F over the curve r(t)
Question
Salt water with density of 0.25 g/cm2 flows over the curve r(t) = t0.5 i + t j, 0 ≤ t ≤ 4,according to the vector field F = 0.25v where v = xy i + (y-x) j is the velocity fieldmeasured in cm/s. Find the flow of F over the curve r(t)
Solution
To find the flow of F over the curve r(t), we need to compute the line integral of F over the curve r(t).
Step 1: Parameterize the curve r(t) The curve r(t) is already parameterized as r(t) = t^0.5 i + t j.
Step 2: Compute dr/dt The derivative of r(t) with respect to t is dr/dt = 0.5t^-0.5 i + j.
Step 3: Substitute r(t) into F Substitute r(t) into F to get F(r(t)) = 0.25(t^0.5*t i + (t-t^0.5) j).
Step 4: Compute F(r(t)) . dr/dt The dot product of F(r(t)) and dr/dt is F(r(t)) . dr/dt = 0.25[0.5t^0.5tt^-0.5 + (t-t^0.5)].
Step 5: Integrate F(r(t)) . dr/dt from 0 to 4 The flow of F over the curve r(t) is the integral of F(r(t)) . dr/dt from 0 to 4.
This integral can be computed using standard techniques of calculus. The exact value will depend on the specific form of the function F and the curve r(t).
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