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1.Find the number of odd days in first 1500 years?      a.0  b.1  c.2  d.3

Question

1.Find the number of odd days in first 1500 years?      a.0  b.1  c.2  d.3

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Solution

To find the number of odd days in the first 1500 years, we need to consider the concept of leap years.

  1. Determine the number of leap years in the given time period. A leap year occurs every 4 years, except for years that are divisible by 100 but not divisible by 400.

  2. Divide the total number of years (1500) by 4 to find the number of leap years. In this case, 1500 divided by 4 equals 375 leap years.

  3. Subtract the number of leap years from the total number of years to find the number of non-leap years. In this case, 1500 minus 375 equals 1125 non-leap years.

  4. Calculate the number of odd days in the leap years. Since each leap year has 2 odd days (1 extra day in February and 1 extra day in the year), multiply the number of leap years by 2. In this case, 375 leap years multiplied by 2 equals 750 odd days.

  5. Calculate the number of odd days in the non-leap years. Since each non-leap year has 1 odd day (1 extra day in the year), multiply the number of non-leap years by 1. In this case, 1125 non-leap years multiplied by 1 equals 1125 odd days.

  6. Add the number of odd days in the leap years and the number of odd days in the non-leap years. In this case, 750 odd days plus 1125 odd days equals 1875 odd days.

  7. Divide the total number of odd days by 7 to find the remainder. The remainder represents the number of odd days left after dividing by 7. In this case, 1875 divided by 7 equals 267 remainder 6.

  8. The remainder of 6 indicates that there are 6 odd days in the first 1500 years.

Therefore, the answer is d. 3

This problem has been solved

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