The Caldwells are moving across the country. Mr. Caldwell leaves 2.52.5 hours before Mrs. Caldwell. If he averages 45mph45mph and she averages 55mph55mph, how many hours will it take Mrs. Caldwell to catch up to Mr. Caldwell?
Question
The Caldwells are moving across the country. Mr. Caldwell leaves 2.52.5 hours before Mrs. Caldwell. If he averages 45mph45mph and she averages 55mph55mph, how many hours will it take Mrs. Caldwell to catch up to Mr. Caldwell?
Solution
Step 1: Determine how far Mr. Caldwell travels before Mrs. Caldwell starts. This is done by multiplying his speed by the time he leaves before her. So, 45 mph * 2.5 hours = 112.5 miles.
Step 2: Now, we need to find out how long it will take Mrs. Caldwell to cover this 112.5 miles gap. Since they are moving in the same direction, we subtract Mr. Caldwell's speed from Mrs. Caldwell's speed to find out how much faster she is traveling. So, 55 mph - 45 mph = 10 mph.
Step 3: Finally, we divide the distance Mr. Caldwell traveled by the difference in their speeds to find out how long it will take Mrs. Caldwell to catch up. So, 112.5 miles / 10 mph = 11.25 hours.
Therefore, it will take Mrs. Caldwell 11.25 hours to catch up to Mr. Caldwell.
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