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For many purposes we can treat ammonia NH3 as an ideal gas at temperatures above its boiling point of −33.°C.Suppose the temperature of a sample of ammonia gas is raised from 24.0°C to 69.0°C, and at the same time the pressure is decreased by 15.0%.

Question

For many purposes we can treat ammonia NH3 as an ideal gas at temperatures above its boiling point of −33.°C.Suppose the temperature of a sample of ammonia gas is raised from 24.0°C to 69.0°C, and at the same time the pressure is decreased by 15.0%.

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Solution

It seems like you're asking for the final volume of the ammonia gas after the changes in temperature and pressure. However, you didn't provide the initial volume of the gas.

In general, you can use the combined gas law to solve this problem. The combined gas law is:

P1V1/T1 = P2V2/T2

Where: P1 = initial pressure V1 = initial volume T1 = initial temperature (in Kelvin) P2 = final pressure V2 = final volume (what we're solving for) T2 = final temperature (in Kelvin)

First, convert the temperatures from Celsius to Kelvin by adding 273.15.

T1 = 24.0°C + 273.15 = 297.15 K T2 = 69.0°C + 273.15 = 342.15 K

Next, calculate the final pressure. If the pressure is decreased by 15%, then the final pressure is 85% of the initial pressure, or 0.85*P1.

Substitute all the known values into the combined gas law and solve for V2.

Please provide the initial volume and pressure so I can help you calculate the final volume.

This problem has been solved

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