An object is put one by one in three liquids having different densities. The object floats with 1/9, 2/11 and 3/7 parts of their volumes outside the liquid surface in liquids d1, d2 and d3 respectively. Which of the following statement is correct? a.d1 > d2 > d3b.d1 < d2 < d3c. d1 < d2 > d3d. d1 > d2 < d3
Question
An object is put one by one in three liquids having different densities. The object floats with 1/9, 2/11 and 3/7 parts of their volumes outside the liquid surface in liquids d1, d2 and d3 respectively. Which of the following statement is correct? a.d1 > d2 > d3b.d1 < d2 < d3c. d1 < d2 > d3d. d1 > d2 < d3
Solution
To determine the correct statement, we need to compare the densities of the three liquids. Let's analyze the given information:
- In liquid d1, the object floats with 1/9 of its volume outside the liquid surface.
- In liquid d2, the object floats with 2/11 of its volume outside the liquid surface.
- In liquid d3, the object floats with 3/7 of its volume outside the liquid surface.
From this information, we can infer that the density of liquid d3 is the lowest, as the object floats with the largest portion of its volume outside the liquid surface. Similarly, the density of liquid d1 is the highest, as the object floats with the smallest portion of its volume outside the liquid surface.
Therefore, the correct statement is:
d1 > d2 > d3
So, option a. d1 > d2 > d3 is the correct answer.
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