The tables represent two linear functions in a system.xy−6−22−3−1002314xy−6−30−3−210−123−3What is the solution to this system?Responses(−133,−25)negative 13 thirds comma negative 25(−13,−50)negative 13 comma negative 50(−14,−54)negative 14 comma negative 54(−143,−54)
Question
The tables represent two linear functions in a system.xy−6−22−3−1002314xy−6−30−3−210−123−3What is the solution to this system?Responses(−133,−25)negative 13 thirds comma negative 25(−13,−50)negative 13 comma negative 50(−14,−54)negative 14 comma negative 54(−143,−54)
Solution
I'm sorry, but the tables you provided are not clearly formatted, which makes it difficult to understand the data. Could you please reformat the tables or provide the equations of the two linear functions? This will help me provide the correct solution to the system.
Similar Questions
x𝑥 y𝑦 00 −6−6 11 −4.5−4.5 22 −3−3 33 −1.5−1.5 x𝑥 y𝑦 00 6.16.1 11 2.12.1 22 −1.9−1.9 33 −5.9−5.9 Complete the statements about the system of linear equations represented by the tables.The equation representing the left table is.The equation representing the right table is.The solution to the system of equations is
Which system has no solution?Responsesy=9x+6.25−18x+2y=12.5y is equal to 9 x plus 6 point 2 5; negative 18 x plus 2 y is equal to 12 point 5y=3x+9x+8y=12.3y is equal to 3 x plus 9; x plus 8 y is equal to 12 point 3y=4.5x−5−3x+2y=6y is equal to 4 point 5 x minus 5; negative 3 x plus 2 y is equal to 6y=−3x+86x+2y=−4.5
2x - 3y = 165x - 3y = 13Solve the system of equations.Responses(5, −2)(5, −2)
Which table represents a linear function?Responsesxy1328315421x y 1 3 2 8 3 15 4 21xy1329327481x y 1 3 2 9 3 27 4 81xy13293349x y 1 3 2 9 3 3 4 9xy1327311415
An equivalent equation has been written by multiplying the second equation by 22.4x−9y=74𝑥−9𝑦=7→→4x−9y=74𝑥−9𝑦=72(−2x+3y=4)2(−2𝑥+3𝑦=4)→→−4x+6y=8−4𝑥+6𝑦=8What is the solution to the system?Responses(−5,−192)negative 5 comma negative 19 halves(−152,−113)negative 15 halves comma negative 11 thirds(−1910, 115)negative 19 tenths comma 1 fifteenth(−192,−5)
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