A capacitor of capacitance 16 𝜇𝐹 is charged to 200 V and the plates. Now, the plates of thecapacitors are connected to a resistor of 50 ohms. Calculate the heat produced across the resistor.
Question
A capacitor of capacitance 16 𝜇𝐹 is charged to 200 V and the plates. Now, the plates of thecapacitors are connected to a resistor of 50 ohms. Calculate the heat produced across the resistor.
Solution
The heat produced in a resistor when a capacitor discharges through it can be calculated using the formula:
Q = 1/2 * C * V^2
where: Q is the heat produced, C is the capacitance of the capacitor, and V is the voltage across the capacitor.
Given: C = 16 μF = 16 * 10^-6 F (converting microfarads to farads) V = 200 V
Substituting these values into the formula, we get:
Q = 1/2 * 16 * 10^-6 F * (200 V)^2 Q = 0.5 * 16 * 10^-6 * 40000 Q = 0.32 Joules
So, the heat produced across the resistor is 0.32 Joules.
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