An object 5 cm in length is held 25 cm away from a converging lens offocal length 10 cm. Draw the ray diagram and find the position, size andthe nature of the image formed.

To solve this problem, we will use the lens formula and magnification formula.

1. Lens Formula: 1/f = 1/v - 1/u Where: f = focal length of the lens = 10 cm u = object distance = -25 cm (It's negative because the object is on the opposite side of the light source) v = image distance (which we are trying to find)

2. Substitute the given values into the lens formula: 1/10 = 1/v - (-1/25) Simplify to get: 1/10 = 1/v + 1/25 Subtract 1/25 from both sides to get: 1/10 - 1/25 = 1/v Simplify to get: 1.5/25 = 1/v Therefore, v = 25/1.5 = 16.67 cm

The image is formed on the opposite side of the object, so the image distance is positive.

3. Magnification Formula: m = -v/u Substitute the values we have: m = -16.67 / -25 = 0.67

The magnification is less than 1, which means the image is diminished.

4. To find the size of the image, multiply the object size by the magnification: Size of image = object size * magnification Size of image = 5 cm * 0.67 = 3.35 cm

So, the image is 3.35 cm in size, it is real, inverted and diminished.

As for the ray diagram, it's not possible to draw it here, but you can easily find instructions on how to draw it online. The basic idea is to draw two rays, one parallel to the principal axis which will pass through the focal point after refraction, and one through the center of the lens which will go straight without bending. The point where the two rays meet on the other side of the lens is where the image is formed.