The vertex of a quadratic function is given by the formula (-b/2a, f(-b/2a)).

Given the quadratic function f(x) = x^2 + 3x - 5, the coefficients are a = 1, b = 3, and c = -5.

Step 1: Calculate -b/2a to find the x-coordinate of the vertex.
-b/2a = -3/(2*1) = -3/2 = -1.5

Step 2: Substitute -b/2a into the function to find the y-coordinate of the vertex.
f(-1.5) = (-1.5)^2 + 3*(-1.5) - 5 = 2.25 - 4.5 - 5 = -7.25

So, the vertex of the function is (-1.5, -7.25).

However, this option is not available in the given answer choices. There might be a mistake in the question or the answer choices.

Question

The vertex of a quadratic function is given by the formula (-b/2a, f(-b/2a)).

Given the quadratic function f(x) = x^2 + 3x - 5, the coefficients are a = 1, b = 3, and c = -5.

Step 1: Calculate -b/2a to find the x-coordinate of the vertex.
-b/2a = -3/(2*1) = -3/2 = -1.5

Step 2: Substitute -b/2a into the function to find the y-coordinate of the vertex.
f(-1.5) = (-1.5)^2 + 3*(-1.5) - 5 = 2.25 - 4.5 - 5 = -7.25

So, the vertex of the function is (-1.5, -7.25).

However, this option is not available in the given answer choices. There might be a mistake in the question or the answer choices.

Knowee AI · Accepted Answer

The vertex of a quadratic function is given by the formula (-b/2a, f(-b/2a)).

Given the quadratic function f(x) = x^2 + 3x - 5, the coefficients are a = 1, b = 3, and c = -5.

Step 1: Calculate -b/2a to find the x-coordinate of the vertex.
-b/2a = -3/(2*1) = -3/2 = -1.5

Step 2: Substitute -b/2a into the function to find the y-coordinate of the vertex.
f(-1.5) = (-1.5)^2 + 3*(-1.5) - 5 = 2.25 - 4.5 - 5 = -7.25

So, the vertex of the function is (-1.5, -7.25).

However, this option is not available in the given answer choices. There might be a mistake in the question or the answer choices.

Question 4Tips1 ptsFind the vertex of the following quadratic function:𝑓(𝑥)=𝑥2+3𝑥−5Group of answer choices(−714,−112)(4,−5)(−112,−714)(4,3)