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12345678910#include <stdio.h> int main() { int i = 1, j = 5, result = 0; while (i <= j && result <= 40) { result += i * (j - i + 1); printf("%d ", result); i++; } return result; }

Question

12345678910#include <stdio.h> int main() { int i = 1, j = 5, result = 0; while (i <= j && result <= 40) { result += i * (j - i + 1); printf("%d ", result); i++; } return result; }

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Solution

The code you've posted is written in C language. It's a simple program that uses a while loop to perform a calculation and print the result. Here's a step-by-step explanation:

  1. The program starts with the inclusion of the standard input-output library stdio.h.

  2. The main() function is declared, which is the entry point of the program.

  3. Inside the main() function, three integer variables i, j, and result are declared and initialized. i is set to 1, j is set to 5, and result is set to 0.

  4. A while loop is started, which will continue as long as i is less than or equal to j and result is less than or equal to 40.

  5. Inside the loop, result is incremented by the product of i and (j - i + 1).

  6. The value of result is then printed to the console.

  7. The variable i is incremented by 1.

  8. The loop continues until i is greater than j or result is greater than 40.

  9. The function then returns the value of result.

  10. The program ends.

The output of this program will be the values of result at each iteration of the loop, printed on the console.

This problem has been solved

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