A simple series circuit is composed of a 9 volt battery and two 1 ohm resistors and an ammeter (current meter) to measure the current flow in the circuit.Since the resistors have same resistance (1 ohm), what will happen if one of the resistors is removed from the circuit and is replaced by a wire to complete the circuit?A The current that is moving through the circuit would increase.B The voltage of the circuit would increase.C The current that is moving through the circuit would decrease.D The voltage of the circuit would decrease.
Question
A simple series circuit is composed of a 9 volt battery and two 1 ohm resistors and an ammeter (current meter) to measure the current flow in the circuit.Since the resistors have same resistance (1 ohm), what will happen if one of the resistors is removed from the circuit and is replaced by a wire to complete the circuit?A The current that is moving through the circuit would increase.B The voltage of the circuit would increase.C The current that is moving through the circuit would decrease.D The voltage of the circuit would decrease.
Solution
The answer is A. The current that is moving through the circuit would increase.
Here's why:
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Ohm's law states that the current (I) through a conductor between two points is directly proportional to the voltage (V) across the two points, and inversely proportional to the resistance (R) between them. It is usually formulated as I = V/R.
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In the original circuit, the total resistance is the sum of the resistances of the two resistors, which is 1 ohm + 1 ohm = 2 ohms. The battery provides a constant voltage of 9 volts. So, the current through the circuit is I = V/R = 9V/2Ω = 4.5A.
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If one of the resistors is removed and replaced by a wire, the wire is assumed to have negligible resistance. So, the total resistance in the circuit drops to 1 ohm.
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Now, if we apply Ohm's law again, the current through the circuit is I = V/R = 9V/1Ω = 9A.
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Therefore, the current that is moving through the circuit would increase.
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