Suppose the linear regression line y = 2.1x + 130 predicts sales based on the money spent on advertising. If x represents the dollars spent in advertising, and y represents the company sales in dollars, about how much can the company expect in sales if it spends $50 in advertising?A.$650B.$105C.$323D.$235

Suppose the linear regression line y = 3.009x – 77.131 predicts a pizza parlor's profits based on the number of pizzas sold. If x represents the number of pizzas sold, and y represents the pizza parlor's profits in dollars, about how much can the pizza parlor expect in profits if it sells 275 pizzas?A.$825B.$750C.$675D.$900SUBMITarrow_backPREVIOUS

A regression analysis between sales (in $1000) and advertising (in $100) yielded the least squares line = 75 +6x. This implies that if $800 is spent on advertising, then the predicted amount of sales (in dollars) is:Group of answer choices$487 500.$12 300.$123 000.$4875.

A regression analysis between y, sales (in $1000) and x, advertising (in $) yielded the least squares line  = 60 + 5x. We can interpret the slope by saying that we estimate for each extra $1 spent on advertising that sales will increase by $5 000, on average.Group of answer choicesTrueFalse

Regression analysis was applied between sales (in $1,000) and advertising (in $100), and the following regression function was obtained.y-hat = 87 + 7.8 xBased on the above estimated regression line, if advertising is $11,924, then the point estimate for sales (in dollars) is

Question 41 ptsUse the data given below to answer the following question(s).Following is an extract from the database of a construction company. The table shows the heightof walls in feet and the cost of raising them. The estimated simple linear regression equation isgiven as Ŷ = b0 + b1X. (Hint: Use Excel functions).What is the estimated cost of raising a 10-inch wall?Group of answer choices1505.7861103.578968.61091123.008