Two triangles are similar. One has sides of 8 m, 5 m, and 6 m. If the longest side of the second triangle is 5 m, what are the length of the shortest side of the second triangle? (Answer to two decimal places.)
Question
Two triangles are similar. One has sides of 8 m, 5 m, and 6 m. If the longest side of the second triangle is 5 m, what are the length of the shortest side of the second triangle? (Answer to two decimal places.)
Solution
To solve this problem, we need to understand that similar triangles have proportional sides.
Step 1: Identify the longest side of the first triangle. In this case, it's 8 m.
Step 2: Set up a proportion using the longest sides of both triangles. The longest side of the second triangle is given as 5 m. So, the proportion is 8/5.
Step 3: To find the shortest side of the second triangle, we set up a proportion using the shortest side of the first triangle (which is 5 m) and the unknown side of the second triangle (let's call it x). So, the proportion is 5/x = 8/5.
Step 4: Solve for x by cross-multiplying. This gives us 55 = 8x, or 25 = 8x.
Step 5: Divide both sides by 8 to solve for x. This gives us x = 25/8 = 3.125 m.
So, the shortest side of the second triangle is approximately 3.13 m (rounded to two decimal places).
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