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Two triangles are similar. One has sides of 8 m, 5 m, and 6 m. If the longest side of the second triangle is 5 m, what are the length of the shortest side of the second triangle? (Answer to two decimal places.)

Question

Two triangles are similar. One has sides of 8 m, 5 m, and 6 m. If the longest side of the second triangle is 5 m, what are the length of the shortest side of the second triangle? (Answer to two decimal places.)

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Solution

To solve this problem, we need to understand that similar triangles have proportional sides.

Step 1: Identify the longest side of the first triangle. In this case, it's 8 m.

Step 2: Set up a proportion using the longest sides of both triangles. The longest side of the second triangle is given as 5 m. So, the proportion is 8/5.

Step 3: To find the shortest side of the second triangle, we set up a proportion using the shortest side of the first triangle (which is 5 m) and the unknown side of the second triangle (let's call it x). So, the proportion is 5/x = 8/5.

Step 4: Solve for x by cross-multiplying. This gives us 55 = 8x, or 25 = 8x.

Step 5: Divide both sides by 8 to solve for x. This gives us x = 25/8 = 3.125 m.

So, the shortest side of the second triangle is approximately 3.13 m (rounded to two decimal places).

This problem has been solved

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