What will be the output of the program?public class Test { public static void main(String args[]) { int i = 1, j = 0; switch(i) { case 2: j += 6; case 4: j += 1; default: j += 2; case 0: j += 4; } System.out.println("j = " + j); } }j = 0j = 2j = 4j = 6
Question
What will be the output of the program?public class Test { public static void main(String args[]) { int i = 1, j = 0; switch(i) { case 2: j += 6; case 4: j += 1; default: j += 2; case 0: j += 4; } System.out.println("j = " + j); } }j = 0j = 2j = 4j = 6
Solution
The output of the program will be "j = 2".
Here's the step by step explanation:
-
The program starts with the declaration of the main method, which is the entry point of any Java program.
-
Two integer variables i and j are declared and initialized. i is initialized to 1 and j is initialized to 0.
-
A switch statement is then started with i as the controlling expression.
-
The switch statement checks each case against the value of i. If a match is found, the code following that case statement is executed.
-
In this case, i is 1. But there is no case for 1 in the switch statement.
-
When no case matches, the default case is executed. Here, the default case adds 2 to j. So, j becomes 2.
-
After executing the default case, the program does not break or exit the switch statement. Instead, it continues to the next case. However, there are no cases after the default case in this program.
-
Finally, the value of j is printed, which is 2. So, the output of the program is "j = 2".
Similar Questions
What will be the output of the program?public class Switch2 { final static short x = 2; public static int y = 0; public static void main(String [] args) { for (int z=0; z < 4; z++) { switch (z) { case x: System.out.print("0 "); default: System.out.print("def "); case x-1: System.out.print("1 "); break; case x-2: System.out.print("2 "); } } }}0 def 12 1 0 def 12 1 0 def def2 1 0 def 1 def 1
What will be the output of the program?int i = 1, j = -1; switch (i) { case 0, 1: j = 1; /* Line 4 */ case 2: j = 2; default: j = 0; } System.out.println("j = " + j); j = -1j = 0j = 1Compilation fails.
What all gets printed when the following program is compiled and run.public class Test{ public static void main(String args[]){ int i, j=1; i = (j>1)?2:1; switch(i){ case 0: System.out.println(0); break; case 1: System.out.println(1); case 2: System.out.println(2); break; case 3: System.out.println(3); break; } }}01212
What will be the output of the following code?public class Solution { public static void main(String args[]) { int i = 5; switch(i) { case 1: System.out.print("Case 1" + " "); break; case 2: System.out.print("Case 2" + " "); break; case 3: System.out.print("Case 3" + " "); break; default: System.out.print("Value of i is greater than 3" + " "); } } }Options: Pick one correct answer from belowCase 1Case 2Case 3Value of i is greater than 3PrevSubmit MCQNext
e correct answerWhat is the output of the following Java program?class Main { public static void main(String args[]) { final int i; i = 20; i = 30; System.out.println(i); }}
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.